\(3Fe+2O_2\rightarrow Fe_3O_4\)
0,1 0,1/3
\(m_{Fe_3O_4}=\dfrac{0.1}{3}\cdot\left(65\cdot3+16\cdot4\right)=\dfrac{259}{30}\left(g\right)\)
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\(3Fe+2O_2\rightarrow Fe_3O_4\)
0,1 0,1/3
\(m_{Fe_3O_4}=\dfrac{0.1}{3}\cdot\left(65\cdot3+16\cdot4\right)=\dfrac{259}{30}\left(g\right)\)