Question

\(\dfrac{x}{2x+2}-\dfrac{2x}{x^2-2x-3}=\dfrac{x}{6-2x}\)

Giúp mk với

Answer 1

đk: x khác -1; 3

\(\dfrac{x}{2\left(x+1\right)}-\dfrac{2x}{\left(x-3\right)\left(x+1\right)}=\dfrac{x}{2\left(3-x\right)}\)

<=> \(\dfrac{x}{2\left(x+1\right)}-\dfrac{2x}{\left(x-3\right)\left(x+1\right)}+\dfrac{x}{2\left(x-3\right)}=0\)

<=> \(\dfrac{x\left(x-3\right)-4x+x\left(x+1\right)}{2\left(x+1\right)\left(x-3\right)}=0\)

<=> \(x^2-3x-4x+x^2+x=0\)

<=> 2x² - 6x = 0

<=> 2x(x-3) = 0

Mà x khác 3

<=> 2x = 0

<=> x = 0