\(\Leftrightarrow5\left(x+1\right)+8\left(2-x\right)< =30x-9\)
=>5x+5+16-8x<=30x-9
=>-3x+21<=30x-9
=>-33x<=-30
hay x>=10/11
\(\dfrac{5x+5}{10}+\dfrac{16-8x}{10}-\dfrac{30x}{10}+\dfrac{9}{10}\le0\)
\(\Leftrightarrow5x+5+16-8x-30x+9\le0\)
<=> 30 -33x \(\le0\)
=> x \(\le\dfrac{30}{33}=\dfrac{10}{11}\)