Question

\(\dfrac{x-3}{5}\)+\(\dfrac{1+2x}{3}\)=6

Answer 1

<=>\(\dfrac{3.\left(x-3\right)}{3.5}+\dfrac{5\left(1+2x\right)}{5.3}=6\)

<=>\(\dfrac{3x-9+5+10x}{15}=6\)

<=>13x-4=90

<=>13x=94

<=>x=\(\dfrac{94}{13}\)

Answer 2

<=>3x−9+5+10x15=63x−9+5+10x15=6

<=>13x-4=90

<=>13x=94

<=>x=