\(\dfrac{x-17}{33}+\dfrac{x-21}{29}+\dfrac{x}{25}=4\)
\(\dfrac{x-17}{33}+\dfrac{x-21}{29}+\dfrac{x}{25}-4=0\)
\(\dfrac{\left(x-17\right)\times725}{33\times725}+\dfrac{\left(x-21\right)\times825}{29\times825}+\dfrac{x\times957}{25\times957}-\dfrac{4\times23925}{23925}=0\)
\(725x-12325+825x-17325+957x-95700=0\)
\(2507x-125350=0\)
\(2507x=125350\)
\(x=50\)
Nếu mà theo cách x - 50 = 0 thì bạn theo cách này nha:
\(\dfrac{x-17}{33}+\dfrac{x-21}{29}+\dfrac{x}{25}=4\)
\(\dfrac{x-17}{33}+\dfrac{x-21}{29}+\dfrac{x}{25}-4=0\)
\(\dfrac{x-17}{33}-1+\dfrac{x-21}{29}-1+\dfrac{x}{25}-2=0\)
\(\dfrac{x-50}{33}+\dfrac{x-50}{29}+\dfrac{x-50}{25}=0\)
\(\left(x-50\right)\left(\dfrac{1}{33}+\dfrac{1}{29}+\dfrac{1}{5}\right)=0\)
Vì \(\dfrac{1}{33}+\dfrac{1}{29}+\dfrac{1}{25}>0\)
=> \(x-50=0\)
=> \(x=50\)
da co cach nao de chung minh x-50=0 roi tinh k ak
tai mik dg lm theo cach do ak
