Các câu hỏi tương tự
19 tháng 7 2023 lúc 13:20
so sánh các số hữu tỉ sau bằng cách hợp lí:
a) -0,2; \(\dfrac{1}{1000}\)
b) \(\dfrac{\text{13}}{\text{-35}};\dfrac{\text{-11}}{\text{28}}\)
c) \(\dfrac{2022}{-2021};\dfrac{-1995}{1996}\)
d) \(\dfrac{\text{-18}}{\text{13}};\dfrac{\text{181818}}{\text{131313}}\)
11 tháng 7 2023 lúc 14:29
Tìm x:
a) dfrac{-12}{17} dfrac{x}{17} dfrac{-8}{17}
b) dfrac{-1}{2} x dfrac{5}{3}
c) 3,456 x le 7,89
d) 5,82 overline{text{5,8x0}} 5,845
e) 32, 82 overline{text{3x, 850}} 35,845
Đọc tiếp
Tìm x:
a) \(\dfrac{-12}{17}\) < \(\dfrac{x}{17}\) < \(\dfrac{-8}{17}\)
b) \(\dfrac{-1}{2}< x< \dfrac{5}{3}\)
c) 3,456 < x \(\le\) 7,89
d) 5,82 < \(\overline{\text{5,8x0}}\) < 5,845
e) 32, 82 < \(\overline{\text{3x, 850}}\) < 35,845
Cho \(\dfrac{\text{x}}{\text{2}}=\dfrac{\text{y}}{\text{3}}=\dfrac{\text{z}}{\text{5}}\). Tìm x,y,z biết
a) x + y + z = 40
b) x - 3y + 2z = 9
c) x -y + z = 28
d) 3x + 2y = 24
Cho x + 3y - 2z = 36. Tìm x,y,z biết
a) \(\dfrac{\text{x-1}}{\text{3}}=\dfrac{\text{y+2}}{\text{4}}=\dfrac{\text{z-2}}{\text{3}}\)
b) \(\dfrac{\text{x}}{\text{4}}=\dfrac{\text{y}}{\text{3}};\dfrac{\text{y}}{\text{2}}=\dfrac{\text{z}}{\text{5}}\)
c) 9x = 5y ; 2x = z
d) 2x = 3y = 4z
20 tháng 10 2023 lúc 20:08
a)\(\left(\dfrac{5}{9}-\dfrac{\sqrt{9}}{12}\right):\dfrac{3}{4}+\dfrac{11}{3}:\dfrac{3}{4}\) b)\(\left(0,\left(3\right)+\dfrac{\text{|}-2\text{|}}{3}\right):\dfrac{\sqrt{25}}{4}-\left(2^3+3^2\right)^0\)
Cho x + 3y - 2z = 36 . Tìm x,y,z biết :
a)\(\dfrac{\text{x-1}}{\text{3}}=\dfrac{\text{y+2}}{\text{4}}=\dfrac{\text{z-2}}{\text{3}}\)
b)\(\dfrac{\text{x}}{\text{4}}=\dfrac{\text{y}}{3};\dfrac{\text{y}}{\text{2}}=\dfrac{\text{z}}{\text{5}}\)
c) 9x = 5y ; 2x = z
d) 2x = 3y = 4z
Thực hiện phép tính(hợp lý nếu có thể):
20\(\dfrac{\text{2}}{\text{5}}\) : \(\dfrac{\text{5}}{\text{6}}\) - 35\(\dfrac{\text{2}}{\text{3}}\) : \(\dfrac{\text{5}}{\text{6}}\) -|-\(\dfrac{\text{3}}{\text{4}}\)|
Cho số hữu tỉ x=\(\dfrac{a+11}{a},a\text{∈}Z,a\text{ ≠}0\)
CMR: A=\(\dfrac{\text{|x|}}{2008+\text{|x|}}\)+\(\dfrac{\text{|y|}}{2008+\text{|y|}}\)> hoặc = \(\dfrac{\text{|x−y|}}{2008+\text{|x−y|}}\)