\(\dfrac{9\sqrt{6}-12\sqrt{3}}{3\sqrt{6}-3\sqrt{3}}=\dfrac{3\sqrt{6}-4\sqrt{3}}{\sqrt{6}-\sqrt{3}}=\dfrac{\left(3\sqrt{6}-4\sqrt{3}\right)\left(\sqrt{6}+\sqrt{3}\right)}{3}\)
\(=\dfrac{3.6+3\sqrt{18}-4\sqrt{18}-4.3}{3}=\dfrac{6-\sqrt{18}}{3}=\dfrac{6-3\sqrt{2}}{3}=2-\sqrt{2}\)