\(=\dfrac{47}{60}-\dfrac{9}{20}=\dfrac{20}{60}=\dfrac{1}{3}\)
\(\dfrac{47}{60}-\left(\dfrac{1}{5}+\dfrac{1}{4}\right)\\ =\dfrac{47}{60}-\left(\dfrac{4}{20}+\dfrac{5}{20}\right)\\ =\dfrac{47}{60}-\dfrac{9}{20}\\ =\dfrac{47}{60}-\dfrac{27}{60}\\ =\dfrac{20}{60}\\ =\dfrac{1}{3}\)