Question

\(\dfrac{3}{5}.\dfrac{11}{7}+\dfrac{3}{5}.\left(\dfrac{-4}{7}\right)+\dfrac{2}{5}\)

Answer 1

\(\dfrac{3}{5}\cdot\dfrac{11}{7}+\dfrac{3}{5}\cdot\left(\dfrac{-4}{7}\right)+\dfrac{2}{5}=\dfrac{3}{5}\cdot\left(\dfrac{11}{7}+\dfrac{-4}{7}\right)+\dfrac{2}{5}=\dfrac{3}{5}\cdot1+\dfrac{2}{5}=\dfrac{3}{5}+\dfrac{2}{5}=\dfrac{5}{5}=1\)

Answer 2

=3/5(11/7-4/7)+2/5=3/5+2/5=1

Answer 3

= 3/5 . ( 11/7 + -4/7 ) + 2/5

= 3/5 + ( -1 ) + 2/5

= -3/5 + 2/5

= -1

Answer 4