mn cs thể giải chi tiết câu hỏi này dc ko '-'
\(\dfrac{3}{7}\) + 4 = ?
\(\dfrac{5}{9}\) x 3 = ?
\(\dfrac{7}{8}\) - \(\dfrac{2}{9}\)= ?
5 - \(\dfrac{3}{4}\)= ?
\(\dfrac{5}{7}\) : 6 = ?
\(\dfrac{5}{6}\) x \(\dfrac{2}{7}\)= ?
3 + \(\dfrac{3}{4}\)= ?
\(\dfrac{3}{5}x\dfrac{4}{8}\) = ?
5 : \(\dfrac{3}{8}\)= ?
Mong mn trả lời
Điền dấu >,<,= vào chỗ chấm:
\(\dfrac{3}{4}\).....\(\dfrac{12}{16}\) \(\dfrac{5}{6}\)........\(\dfrac{7}{9}\) \(\dfrac{4}{15}\)........\(\dfrac{4}{13}\) \(\dfrac{5}{4}\)-\(\dfrac{5}{6}\).......\(\dfrac{3}{4}\)-\(\dfrac{2}{3}\)
a,\(\dfrac{2}{3}\)x\(\dfrac{5}{2}\):\(\dfrac{9}{5}\)
b,\(\dfrac{1}{3}\)x\(\dfrac{1}{4}\)+\(\dfrac{5}{6}\)
c,\(\dfrac{1}{2}\)-\(\dfrac{7}{8}\):\(\dfrac{7}{4}\)
d,\(\dfrac{6}{5}\)-\(\dfrac{4}{5}\)x\(\dfrac{3}{2}\)
Đặt tính rồi tính :
\(a.\dfrac{5}{6}+\dfrac{2}{5}\)
\(b.\dfrac{6}{5}-\dfrac{3}{4}\)
\(c.\dfrac{9}{16}\times\dfrac{4}{3}\)
\(d.\dfrac{8}{17}:6\)
a,\(\dfrac{4}{9}\) : \(\dfrac{3}{10}\)
b,\(\dfrac{3}{7}\) x \(\dfrac{5}{7}\)
c,\(\dfrac{4}{9}\) : \(\dfrac{3}{2}\)
D \(\dfrac{3}{9}\) + \(\dfrac{5}{6}\) x \(\dfrac{2}{3}\)
E \(\dfrac{2}{7}\) x \(\dfrac{4}{3}\) + \(\dfrac{2}{6}\)
G \(\dfrac{4}{7}\) : 2 + \(\dfrac{4}{7}\)
\(\dfrac{3}{5}+\dfrac{1}{2}+\dfrac{8}{15}\)
\(\dfrac{6}{9}+\dfrac{14}{18}-\dfrac{5}{6}\)
\(\dfrac{9}{20}-\dfrac{3}{5}:\dfrac{4}{1}\)
\(\dfrac{1}{6}+\dfrac{2}{3}\) x \(\dfrac{8}{9}\)
6. ÉT O ÉT
\(\dfrac{9}{7}\) và \(\dfrac{5}{6}\) \(\dfrac{4}{7}\) và \(\dfrac{8}{21}\) \(\dfrac{2}{5};\dfrac{1}{3}\) và \(\dfrac{1}{2}\) \(\dfrac{1}{3};\dfrac{4}{3}\) và\(\dfrac{1}{5}\)
\(\dfrac{3}{4}+\dfrac{5}{8}=?\) 6 - \(\dfrac{3}{7}=?\)
\(\dfrac{3}{4}X\dfrac{2}{5}=?\) \(\dfrac{3}{7}:\dfrac{4}{9}=?\)
a,\(\dfrac{5}{8}\)+\(\dfrac{1}{4}\)\(-\)\(\dfrac{5}{6}\)
b,\(\dfrac{6}{11}\):\(\dfrac{3}{5}\)\(-\)\(\dfrac{2}{3}\)
\(\dfrac{3}{4}\) + 3 \(\dfrac{5}{2}\) x 4 2 - \(\dfrac{7}{8}\)\(\) \(\dfrac{9}{4}\) - 2 5 : \(\dfrac{5}{7}\) \(\dfrac{5}{6}\) : \(\dfrac{2}{4}\) giúp mik vớiii
