Question

\(\dfrac{3}{5}\) + \(\dfrac{-9}{10}\) - \(\dfrac{7}{6}\)

Answer 1

To add these fractions, you'll first need to find a common denominator:

1. For \( \frac{3}{5} \) and \( \frac{-9}{10} \), the common denominator is 10.
2. For \( \frac{7}{6} \), the common denominator is 6.

So, let's rewrite these fractions with a common denominator:

1. \( \frac{3}{5} \) becomes \( \frac{6}{10} \)
2. \( \frac{-9}{10} \) remains the same.
3. \( \frac{7}{6} \) becomes \( \frac{35}{30} \)

Now, add them up:

\[ \frac{6}{10} + \frac{-9}{10} - \frac{35}{30} \]

\[ \frac{6 - 9 - 35}{10} \]

\[ \frac{-38}{10} \]

Now, you can simplify this fraction. Divide both the numerator and denominator by their greatest common divisor, which is 2:

\[ \frac{-19}{5} \]

So, \( \frac{3}{5} + \frac{-9}{10} - \frac{7}{6} = \frac{-19}{5} \)

Answer 2

\(\dfrac{3}{5}+\dfrac{-9}{10}-\dfrac{7}{6}\)

\(=\dfrac{-3}{10}-\dfrac{7}{6}\)

\(=\dfrac{-22}{15}\)

 

Answer 3

    \(\dfrac{3}{5}+\dfrac{-9}{10}-\dfrac{7}{6} \)
= \(\dfrac{18}{30}+\dfrac{-27}{30}-\dfrac{35}{30}\)
= \(\dfrac{18+\left(-27\right)-35}{30}\)
= \(\dfrac{-44}{30}\)
= \(\dfrac{-22}{15}\)
Hoài An