Question

\(\dfrac{2}{x}-\dfrac{1}{x-1}=\dfrac{2x}{x\left(x-2\right)}\)

giúp nhanh vs ạ

Answer 1

đk : x khác 0 ; 1 ; 2 

\(2\left(x-1\right)\left(x-2\right)-x\left(x-2\right)=2x\left(x-1\right)\)

\(\Leftrightarrow2\left(x^2-3x+2\right)-x^2+2x=2x^2-2x\)

\(\Leftrightarrow-6x+4-x^2+2x=-2x\Leftrightarrow x^2+2x-4=0\)

\(\Leftrightarrow\left(x+1\right)^2-5=0\Leftrightarrow\left[{}\begin{matrix}x=-1-\sqrt{5}\\x=-1+\sqrt{5}\end{matrix}\right.\left(tm\right)\)

 

Answer 2

Thấy hơi lạ lạ, mấy bạn coi rồi nói cho mình nha! Cảm ơn~