\(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)
⇔\(0,6\left(2x-1\right)=3.-5\)
⇔\(1,2x-0,6=-15\)
⇔\(1,2x=-14,4\)
⇔\(x=-12\)
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Các câu hỏi tương tự
Tìm x
\(\dfrac{3}{4}x+\dfrac{-1}{2}=\dfrac{-13}{8}\)
\(\left|x\right|+0,25=1,75.3\)
\(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)
Tìm x để biểu thức:
a) A= 0,6 + \(\left|\dfrac{1}{2}-x\right|\) đạt giá trị nhỏ nhất
b) B= \(\dfrac{2}{3}\) - \(\left|2x+\dfrac{2}{3}\right|\) đạt giá trị lớn nhất
\(\dfrac{x-3}{3}=\dfrac{2x+1}{5}\)
\(\dfrac{x+1}{22}=\dfrac{6}{x}\)
\(\dfrac{2x-1}{2}=\dfrac{5}{x}\)
\(\dfrac{2x-1}{21}=\dfrac{3}{2x+1}\)
\(\dfrac{2x+1}{9}=\dfrac{5}{x+1}\)
Tìm x
1,4 . 3x-2 + 2 . 3x+1 4 . 34 + 2 . 372, dfrac{3}{5} . 2x + dfrac{7}{5} . 2x+3 dfrac{3}{5} . 210 + dfrac{7}{5} . 2133,dfrac{5}{3} . 8x+2 - dfrac{3}{5} . 8x dfrac{5}{3} . 811 - dfrac{3}{5} . 894,(dfrac{1}{2} - dfrac{1}{6}).3x+4 - 4 . 3x 316 - 4 . 319Mn làm giúp em với ạ , em cảm ơn !
Đọc tiếp
1,4 . 3x-2 + 2 . 3x+1 = 4 . 34 + 2 . 37
2, \(\dfrac{3}{5}\) . 2x + \(\dfrac{7}{5}\) . 2x+3 = \(\dfrac{3}{5}\) . 210 + \(\dfrac{7}{5}\) . 213
3,\(\dfrac{5}{3}\) . 8x+2 - \(\dfrac{3}{5}\) . 8x = \(\dfrac{5}{3}\) . 811 - \(\dfrac{3}{5}\) . 89
4,(\(\dfrac{1}{2}\) - \(\dfrac{1}{6}\)).3x+4 - 4 . 3x = 316 - 4 . 319
Mn làm giúp em với ạ , em cảm ơn !
2. Tìm x
a. \(\dfrac{4}{5}-3.\left|x\right|=\dfrac{1}{5}\) b. \(4x-\dfrac{1}{2}x+\dfrac{3}{5}x=\dfrac{4}{5}\)
c. (2x-8)(10-5x)=0 d. \(\dfrac{3}{4}+\dfrac{1}{4}\left|2x-1\right|=\dfrac{7}{2}\)
\(\dfrac{2x-1}{203}\)+\(\dfrac{2x-3}{205}\)=\(\dfrac{5-2x}{207}\)-\(\dfrac{2x}{101}\)
\(\dfrac{2x-1}{203}\)+\(\dfrac{2x-3}{205}\)=\(\dfrac{5-2x}{207}\)-\(\dfrac{2x}{101}\)
a) 2dfrac{1}{2} - x + dfrac{4}{5} dfrac{2}{3} - (-dfrac{4}{7} )
b) -dfrac{4}{7} - x dfrac{3}{5} - 2x
c) (dfrac{3}{8} - dfrac{1}{5} ) + (dfrac{5}{8} - x) dfrac{1}{5}
Đọc tiếp
a) \(2\dfrac{1}{2}\) - x + \(\dfrac{4}{5}\) = \(\dfrac{2}{3}\) - (\(-\dfrac{4}{7}\) )
b) \(-\dfrac{4}{7}\) - x = \(\dfrac{3}{5}\) - 2x
c) (\(\dfrac{3}{8}\) - \(\dfrac{1}{5}\) ) + (\(\dfrac{5}{8}\) - x) = \(\dfrac{1}{5}\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)