Question

\(\dfrac{2+\sqrt{3}}{2-\sqrt{7}}\)

Answer 1

\(=\dfrac{(2+\sqrt3)(2+\sqrt7)}{(2+\sqrt7)(2-\sqrt7)} \\=\dfrac{4+2\sqrt7+2\sqrt3+\sqrt{21}}{-3} \\=\dfrac{-4-2\sqrt7-2\sqrt3-\sqrt{21}}{3}\)