\(\dfrac{25}{2-x}=\dfrac{5}{3}\\ \Rightarrow25.3=5.\left(2-x\right)\\ \Rightarrow75=10-5x\\ \Rightarrow-5x=-65\\ \Rightarrow13\)
\(\Rightarrow5x=-65\\ \Rightarrow-13\)
mik sửa lại
\(\dfrac{25}{2-x}=\dfrac{5}{3}\)
\(\Leftrightarrow\dfrac{75}{3\left(2-x\right)}=\dfrac{5\left(2-x\right)}{3\left(2-x\right)}\)
\(\Leftrightarrow75=10-5x\)
\(\Leftrightarrow5x=10-75\)
\(\Leftrightarrow5x=-65\)
\(\Leftrightarrow x=\dfrac{-65}{5}=-13\)