Question

\(\dfrac{2^{4-x}}{16^5}=32^6\)

Answer 1

\(\Leftrightarrow2^{4-x}=2^{30}\cdot2^{20}=2^{50}\)

=>4-x=50

hay x=-46

Answer 2

\(\dfrac{2^{4-x}}{16^5}=32^6\\ =>2^{4-x}=32^6.16^5=\left(2^5\right)^6.\left(2^4\right)^5=2^{5.6}.2^{4.5}\\ =>2^{4-x}=2^{30}.2^{20}=2^{30+20}=2^{50}\\ =>4-x=50\\ =>x=-46\)

Answer 3

\(\dfrac{2^{4-x}}{16^5}=32^6\)

\(2^{4-x}=32^6.16^5\)

\(2^{4-x}=\left(2^5\right)^6.\left(2^4\right)^5\)

\(2^{4-x}=2^{30}.2^{20}\)

\(2^{4-x}=2^{50}\)

\(\Rightarrow4-x=50\)

\(x=4-50\)

\(x=-46\)

Vậy \(x=-46\)