Question

\((\dfrac{2}{3}+\dfrac{1}{2})^2.\dfrac{5}{7}-\dfrac{1}{6}\) giúp

 

Answer 1

\(=\left(\dfrac{7}{6}\right)^2\cdot\dfrac{5}{7}-\dfrac{1}{6}=\dfrac{49}{36}\cdot\dfrac{5}{7}-\dfrac{1}{6}\)

\(=\dfrac{35}{36}-\dfrac{6}{36}=\dfrac{29}{36}\)

Answer 2

\(=\left(\dfrac{4}{6}+\dfrac{3}{6}\right)^2.\dfrac{5}{7}-\dfrac{1}{6}=\left(\dfrac{7}{6}\right)^2.\dfrac{5}{7}-\dfrac{1}{6}\\ =\dfrac{49}{36}.\dfrac{5}{7}-\dfrac{1}{6}=\dfrac{49.5}{36.7}-\dfrac{1}{6}=\dfrac{7.7.5}{36.7}-\dfrac{1}{6}\\ =\dfrac{35}{36}-\dfrac{1}{6}=\dfrac{35}{36}-\dfrac{6}{36}=\dfrac{35-6}{36}=\dfrac{29}{36}\)