Question

\(\dfrac{1}{4}\)+\(\dfrac{3}{4}\):x= -2

Answer 1

\(\dfrac{1}{4}+\dfrac{3}{4}:x=-2\)

        \(\dfrac{3}{4}:x=\left(-2\right)-\dfrac{1}{4}\)

        \(\dfrac{3}{4}:x=-\dfrac{9}{4}\)

              \(x=\dfrac{3}{4}:\left(-\dfrac{9}{4}\right)\)

              \(x=\dfrac{3}{4}\cdot\left(-\dfrac{4}{9}\right)\)

              \(x=-\dfrac{12}{36}\)

              \(x=-\dfrac{1}{3}\)

 

Answer 2

\(\dfrac{1}{4} + \dfrac{3}{4}:x=-2\)

 

=> \(\dfrac{3}{4}:x=-2-\dfrac{1}{4}\)

 

=> \(\dfrac{3}{4}:x=\dfrac{-9}{4}\)

 

=> \(x = \dfrac{-9}{4}:\dfrac{3}{4}\)

 

=> \(x = \dfrac{ -1}{3}\)

 

Vậy \(x = \dfrac{ -1}{3}\)

Answer 3

Sửa :

\(\dfrac{1}{4} + \dfrac{3}{4}:x=-2\)

 

=> \(\dfrac{3}{4}:x=-2-\dfrac{1}{4}\)

 

=> \(\dfrac{3}{4}:x=\dfrac{-9}{4}\)

 

=> \(x = \dfrac{3}{4} : \dfrac{-9}{4}:\)

 

=> \(x = \dfrac{ -1}{3}\)

 

Vậy \(x = \dfrac{ -1}{3}\)