Question

\(\dfrac{1}{4}+\dfrac{2}{3}x=-2\)

Answer 1

\(\dfrac{1}{4}+\dfrac{2}{3}x=-2\)

\(\dfrac{2}{3}x=-2-\dfrac{1}{4}=-2+\left(-\dfrac{1}{4}\right)\)

\(\dfrac{2}{3}x=-\dfrac{9}{4}\)

\(x=-\dfrac{9}{4}:\dfrac{2}{3}=-\dfrac{9}{4}\cdot\dfrac{3}{2}\)

\(x=-\dfrac{18}{12}=-\dfrac{3}{2}\)

 

Answer 2

`1/4 + 2/3x = -2`

`=> 2/3x    = (-2)- 1/4`

`=>  2/3x   = -9/4`

`=>       x   = (-9/4) : 2/3`

`=>       x   = -27/8`