Question

\(\dfrac{1}{3}\)x+\(\dfrac{2}{3}\)x=\(\dfrac{-7}{6}\)

Ai đó chỉ bài này với 

Answer 1

`1/3x+2/3x=[-7]/6`

`(1/3+2/3)x=[-7]/6`

`3/3x=[-7]/6`

`x=[-7]/6`

Answer 2

\(x.\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=-\dfrac{7}{6}\)

\(x.1=-\dfrac{7}{6}\)

\(x=-\dfrac{7}{6}:1\)

\(x=-\dfrac{7}{6}\)

Answer 3

$\frac{1}{3}x+\frac{2}{3}x=\frac{-7}{6}$

$(\frac{1}{3}+\frac{2}{3})x=\frac{-7}{6}$

$\frac{3}{3}x=\frac{-7}{6}$

$x=\frac{-7}{6}$

Answer 4

-6/7

Answer 5

  1/3x + 2/3x= -7/6.

( 1/3 + 2/3)x= -7/6

                1x= -7/6

                  x= -7/6.