\(\dfrac{1}{2}x-2=2x+1\)
\(\Leftrightarrow2x-\dfrac{1}{2}x=-2-1\)
\(\Leftrightarrow\dfrac{3}{2}x=-3\)
\(\Leftrightarrow x=-3:\dfrac{3}{2}\)
\(\Leftrightarrow x=-2\)
`1/2x-2=2x+1`
`=> 2x-1/2x=-2-1`
`=> 3/2x=-3`
`=> x=-3 : 3/2`
`=> x=-2`
Vậy `x=-2`
\(\dfrac{1}{2}x-2=2x+1\)
\(\Leftrightarrow2x-\dfrac{1}{2}x=-2-1\)
\(\Leftrightarrow\dfrac{3}{2}x=-3\)
\(\Leftrightarrow x=-3:\dfrac{3}{2}\)
\(\Leftrightarrow x=-2\)
`1/2x-2=2x+1`
`=> 2x-1/2x=-2-1`
`=> 3/2x=-3`
`=> x=-3 : 3/2`
`=> x=-2`
Vậy `x=-2`
\(\dfrac{x-3}{3}=\dfrac{2x+1}{5}\)
\(\dfrac{x+1}{22}=\dfrac{6}{x}\)
\(\dfrac{2x-1}{2}=\dfrac{5}{x}\)
\(\dfrac{2x-1}{21}=\dfrac{3}{2x+1}\)
\(\dfrac{2x+1}{9}=\dfrac{5}{x+1}\)
Tìm x
Tìm x, biết:
a) \(\dfrac{x-2}{2x+1}=\dfrac{2}{3}\)
b) \(\dfrac{x-2}{2x-1}=\dfrac{-1}{3}\)
7x^3-2x^2:-2x^2+(\(\dfrac{5}{4}\)x^2-3x):x-\(\dfrac{1}{2}\)x(x-1)(2x+1)
Bài 1: Thực hiện phép tính
a, (5x-2y)(x\(^2\)-xy+1)
b, (x-1)(x+1)(x+2)
c, \(\dfrac{1}{2}\)x\(^2\)y\(^2\)(2x+y)(2x-y)
d, (x-\(\dfrac{1}{2}\))(x+\(\dfrac{1}{2}\))(4x-1)
e, (x-7)(x+5)-(2x+1)(3-x)
Tìm x :
a) (2x+1)2=\(\dfrac{1}{9}\)
b)\(\sqrt{x+\dfrac{1}{2}}=\dfrac{1}{4}\)
c) \(\dfrac{x+1}{2x-1}=\dfrac{4}{5}\)
Tìm số nguyên x, biết
a) \(-\dfrac{x}{2}+\dfrac{2x}{3}+\dfrac{x+1}{4}+\dfrac{2x+1}{6}=\dfrac{8}{3}\)
b) \(\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}=\dfrac{12}{26}\)
1/ 3 x (x - \(\dfrac{1}{2}\)) - 3 x (x - \(\dfrac{1}{3}\)) - (x - \(\dfrac{1}{2}\)) = 0
2/ \(\dfrac{-2x+1}{3}\) + \(\dfrac{1}{2}\) = \(\dfrac{-1}{3}\)
Tìm x:
\(a\)) \(\dfrac{2}{3}+\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}\)
\(b\)) \(\left(\dfrac{3}{2}\right)^{2x-1}:\left(\dfrac{27}{8}\right)^3=\dfrac{81}{16}\)
\(c\)) \(\dfrac{1}{2}.2^x+4.2^x=9.2^5\)
\(d\)) \(\text{12 - (2x +1)}^2=-69\)
Tìm X
a) (\(\dfrac{1}{4}\) - X) ( X + \(\dfrac{2}{5}\) ) = 0
b) I 2x + 1 I +\(\dfrac{2}{3}\) = 2
c) (2x - 3 )\(^2\) = 36
d) 7\(^x\) + 2 +2 x 7\(^x\) = 357
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)