\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2020x2021}\)
\(=1-\dfrac{1}{2021}=\dfrac{2020}{2021}\)
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
B= \(\dfrac{1}{1x2}\)+\(\dfrac{1}{2x3}\)+\(\dfrac{1}{3x4}\)+.....+\(\dfrac{1}{198x199}\)+\(\dfrac{1}{199x200}\)
20 tháng 9 2023 lúc 11:34
\(\dfrac{1}{1x2}\)+\(\dfrac{1}{2x3}\)+\(\dfrac{1}{3x4}\)+......+\(\dfrac{1}{9x10}\)
Tính bằng cách nhanh nhất
Tìm x biết:
\(\dfrac{x}{x+1}=\dfrac{1}{1x2}+\dfrac{1}{2x3}+\dfrac{1}{3x4}+...+\dfrac{1}{31x32}\)
Trả lời nhanh giúp mìn nhé
Tìm x:
(x -\(\dfrac{1}{3}\) ) x (\(\dfrac{2}{1x2}\)+ \(\dfrac{2}{2x3}\)+ \(\dfrac{2}{3x4}\) + … + \(\dfrac{2}{9x10}\)) = \(\dfrac{3}{4}\)
D=\(\dfrac{5}{1x2}\)+\(\dfrac{5}{2x3}\)+\(\dfrac{5}{3x4}\)+....+\(\dfrac{5}{199x200}\)
E=\(\dfrac{0,5}{1x2}\)+\(\dfrac{0,5}{2x3}\)+\(\dfrac{0,5}{3x4}\)+......+\(\dfrac{0,5}{198x199}\)+\(\dfrac{0,5}{199x200}\)
C=\(\dfrac{2}{1x2}\)+\(\dfrac{2}{2x3}\)+\(\dfrac{2}{3x4}\)+...+\(\dfrac{2}{2018x2019}\)+\(\dfrac{2}{2019x2020}\)
17 tháng 3 2023 lúc 15:10
A = \(\dfrac{1}{2}+\dfrac{1}{2x3}+\dfrac{1}{3x4}+............+\dfrac{1}{9x10}\)
tính nhanh
\(\dfrac{1}{2x3}\)+\(\dfrac{1}{1x2}\)+..................+\(\dfrac{1}{^{\text{64x65}}}\)
\(\left(\dfrac{1}{1x2}+\dfrac{1}{2x3}+........+\dfrac{1}{8x9}+\dfrac{1}{9x10}\right)xX=\dfrac{3}{4}\)