Áp dụng ĐLBTKL: \(m_{O_2}=5,16-3,24=1,92\left(g\right)\)
\(\Rightarrow n_{O_2}=\dfrac{1,92}{32}=0,06\left(mol\right)\)
PTHH: \(4Al+3O_2\xrightarrow[]{t^o}2Al_2O_3\)
0,08<--0,06
\(\Rightarrow\%m_{Al\left(\text{bị oxi hóa}\right)}=\dfrac{0,08.27}{3,24}.100\%=66,67\%\)