Question

Dang 1 va dang 2 nhe

Answer 1

Dạng 2:

a: Ta có: \(\dfrac{2}{3}x+\dfrac{1}{5}=\dfrac{1}{3}\)

\(\Leftrightarrow x\cdot\dfrac{2}{3}=\dfrac{2}{15}\)

hay \(x=\dfrac{1}{5}\)

b: Ta có: \(3\dfrac{2}{5}x-\dfrac{4}{5}=\dfrac{-3}{10}\)

\(\Leftrightarrow x\cdot\dfrac{17}{5}=\dfrac{-3}{10}+\dfrac{4}{5}=\dfrac{1}{2}\)

hay \(x=\dfrac{1}{2}:\dfrac{17}{5}=\dfrac{5}{34}\)

Answer 2

Dạng 2: 

a: \(\dfrac{1}{5}+\dfrac{2}{3}x=\dfrac{1}{3}\)

\(\Leftrightarrow x\cdot\dfrac{2}{3}=\dfrac{2}{15}\)

hay \(x=\dfrac{1}{5}\)