Question

D = 16^8 - 1 / (2 + 1) (2^2 + 1) (2^4 + 1) (2^8 + 1) (2^16 + 1)

Answer 1

       \(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)

\(=2^{32}-1\)

\(=\left(2^4\right)^8-1=16^8-1\)

\(\Rightarrow D=1\)Chúc bạn học tốt.