Question

cứu

Answer 1

a: \(2x-y\sqrt2=5+\left(x+1\right)\cdot\sqrt2\)

=>\(\begin{cases}2x=5\\ -y=x+1\end{cases}\Rightarrow\begin{cases}x=\frac52\\ y=-x-1=-\frac52-1=-\frac72\end{cases}\)

b: \(5x+y-\left(2x-1\right)\cdot\sqrt7=y\sqrt7+2\)

=>\(\left(5x+y\right)+\sqrt7\left(-2x+1\right)=y\sqrt7+2\)

=>\(\begin{cases}5x+y=2\\ -2x+1=y\end{cases}\Rightarrow\begin{cases}5x-2x+1=2\\ y=-2x+1\end{cases}\)

=>\(\begin{cases}3x=1\\ y=-2x+1\end{cases}\Rightarrow\begin{cases}x=\frac13\\ y=-\frac23+1=\frac13\end{cases}\)