\(\dfrac{13}{35}+\dfrac{8}{24}+\dfrac{22}{35}-\dfrac{4}{3}\\ =\left(\dfrac{13}{35}+\dfrac{22}{35}\right)+\left(\dfrac{8}{24}-\dfrac{4}{3}\right)\\ =\dfrac{35}{35}+\left(\dfrac{1}{3}-\dfrac{4}{3}\right)\\ =1-\dfrac{3}{3}\\ =1-1\\ =0\)
\(\dfrac{13}{35}+\dfrac{8}{24}+\dfrac{22}{35}-\dfrac{4}{3}\\ =\left(\dfrac{13}{35}+\dfrac{22}{35}\right)+\left(\dfrac{8}{24}-\dfrac{4}{3}\right)\\ =\dfrac{35}{35}+\left(\dfrac{1}{3}-\dfrac{4}{3}\right)\\ =1-\dfrac{3}{3}\\ =1-1\\ =0\)
Tìm tích của 98 số hạng đầu tiên của dãy
\(1\dfrac{1}{3};1\dfrac{1}{8};1\dfrac{1}{15};1\dfrac{1}{24};1\dfrac{1}{35}\)
\(\dfrac{4^5.9^4}{8^3.27^3}\);\(\dfrac{4^{20}.3^{35}}{2^{37}.27^{12}}\)\(;\dfrac{5^4.20^4}{25^5.4^5};\dfrac{2^{15}.9^4}{6^6.8^3}\)
hãy tính giá trị của biểu thức sau:
C=\(\left|-3\left(-\dfrac{13}{15}-\dfrac{17}{21}\right)\right|-\left|-\dfrac{13}{5}+\dfrac{17}{7}\right|+\left(-12+\dfrac{35}{3}\right):\left|-\dfrac{7}{6}\right|\)
Tìm x
\(a,3-x=x+1,8\)
\(b,2x-5=7x+35\)
\(c,2\left(x+10\right)=3\left(x-6\right)\)
\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)
\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)
\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)
\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)
\(k,7x^2-11=6x^2-2\)
\(m,5\left(x+3.2^3\right)=10^2\)
\(n,\dfrac{4}{9}-(\dfrac{1}{6^2})=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)
\(\dfrac{-1}{2}-\dfrac{-3}{5}-\dfrac{1}{9}-\dfrac{1}{127}-\dfrac{7}{18}+\dfrac{4}{35}-\dfrac{-2}{7}\)
\(\dfrac{1}{2}-\dfrac{-2}{5}+\dfrac{1}{3}+\dfrac{5}{7}-\dfrac{-1}{6}+\dfrac{-4}{35}-\dfrac{1}{41}\)
a)\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}-\dfrac{1}{6}-\dfrac{4}{35}\)
b)\(\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)-\left(5+\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(-6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
c)\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
e)\(\dfrac{2-x}{4}=\dfrac{3x-1}{-3}\)\(\) f)\(\dfrac{x}{7}=\dfrac{x+16}{35}\)
rút gọn phân số
a)\(\dfrac{4^6.3^4.9^5}{6^{12}}\)
b)\(\dfrac{21^2.14.125}{35^2.6}\)
c)\(\dfrac{45^3.20^4.18^2}{180^5}\)
d)\(\dfrac{2^{13}+2^5}{2^{10}+2^2}\)