a: AM=MB
=>M là trung điểm của AB
=>\(AM=\frac12\times AB\)
=>\(S_{AMC}=\frac12\times S_{ABC}\)
Ta có: \(AN=\frac13\times AC\)
=>\(S_{AMN}=\frac13\times S_{AMC}=\frac13\times\frac12\times S_{ABC}=\frac16\times S_{ABC}\)
b: \(S_{AMN}+S_{MNCB}=S_{ABC}\)
=>\(S_{MNCB}=S_{ABC}-\frac16\times S_{ABC}=\frac56\times S_{ABC}\)
\(S_{MNCB}-S_{AMN}=10\)
=>\(\frac56\times S_{ABC}-\frac16\times S_{ABC}=10\)
=>\(\frac23\times S_{ABC}=10\)
=>\(S_{ABC}=10:\frac23=10\times\frac32=15\left(\operatorname{cm}^2\right)\)




