Lại là tui đây:>
\(sin5x=-1\Leftrightarrow sin5x=\dfrac{-\pi}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}5x=-\dfrac{\pi}{2}+k2\pi\\5x=\pi-\left(-\dfrac{\pi}{2}\right)+k2\pi\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-\pi}{10}+\dfrac{k2\pi}{5}\\x=\dfrac{3\pi}{10}+\dfrac{k2\pi}{5}\end{matrix}\right.\left(k\in Z\right)\)