2a+b+c+d/a=a+2b+c+d/b=a+b+2c+d/c=a+b+c+2d/d
\(\Leftrightarrow\)a+a+b+c+d/a=a+b+b+c+d/b=a+b+c+c+d/c=a+b+c+d+d/d
\(\Leftrightarrow\)a+b+c+d/a+1=a+b+c+d/b+1=a+b+c+d/c+1=a+b+c+d/d+1
\(\Leftrightarrow\)a+b+c+d/a=a+b+c+d/b=a+b+c+d/c=a+b+c+d/d
Dến đây ta xét 2 TH:
a+b+c+d≠0
a+b+c+d=0
Ta có: (2a+b+c+d/a)-1=(a+2b+c+d/b)-1=(a+b+2c+d/d)-1=(a+b+c+2d/d)-1
=>a+b+c+d/a=a+c+b+d/b=a+b+c+d/c=a+b+c+d/d
=>a=b=c=d (1)
Ta lại có: a+b+c+d/a=a+b+c+d/b=a+b+c+d/c=a+b+c+d/d
=> a+b+c+d/a=a+b+c+d/b=a+b+c+d/c=a+b+c+d/d=(a+b+c+d+a+b+c+d+a+b+c+d+a+b+c+d+)/a+b+c+d
=4(a+b+c+d)/a+b+c+d=4 (2)
Từ (1) và (2) => a=b=c=d=1
=> M=1+1/1+1 + 1+1+/1+1 + 1+1/1+1 + 1+1/1+1
=4