gọi \(\text{Ư}CLN_{\left(3a+4;2a+3\right)}=d\)
\(\Rightarrow\hept{\begin{cases}3a+4⋮d\\2a+3⋮d\end{cases}\Rightarrow\hept{\begin{cases}2\left(3a+4\right)⋮d\\3\left(2a+3\right)⋮d\end{cases}\Rightarrow}\hept{\begin{cases}6a+8⋮d\\6a+9⋮d\end{cases}}}\)
\(\Rightarrow6a+9-\left(6a+8\right)⋮d\)
\(\Rightarrow6a+9-6a-8⋮d\)
\(\Rightarrow1⋮d\)
\(\Rightarrow d=1\)
vậy phân số \(\frac{3a+4}{2a+3}\) là phân số tối giản
\(\frac{3a+4}{2a+3}\)
Gọi d = ƯCLN ( 3a + 4 ; 2a + 3 )
Ta có :
3a + 4 \(⋮\)d ; 2a + 3 \(⋮\)d
=> 2 ( 3a + 4 ) \(⋮\)d ; 3 ( 2a + 3 ) \(⋮\)d
=> 6a + 8 \(⋮\)d ; 6a + 9 \(⋮\)d
=> ( 6a + 9 ) - ( 6a + 8 ) \(⋮\)d
=> 1 \(⋮\)d
Vậy ...........
