Question

chứng tỏ A chia hết cho 6 với A= 2+2²+2³+2⁴+...+2¹⁰⁰

Answer 1

\(A=\left(2+2^2\right)+2^2\left(2+2^2\right)+...+2^{98}\left(2+2^2\right)\)

\(=6+2^2.6+...+2^{98}.6=6\left(1+2^2+...+2^{98}\right)⋮6\)