a) \(\dfrac{a}{c}=\dfrac{a+b}{c+d}\)
=> a(c + d) = c(a + b)
=> ac + ad = ac + bc
=> ad = bc \(\Leftrightarrow\dfrac{a}{b}=\dfrac{c}{d}\)
b) \(\dfrac{b}{d}=\dfrac{a-b}{c-d}\)
=> b(c - d) = d(a - b)
=> bc - bd = ad - bd
=> bc = ad \(\Leftrightarrow\dfrac{a}{b}=\dfrac{c}{d}\)