Ta có
+ ) ( x – 1 ) 3 + 2 ( x – 1 ) 2 = ( x – 1 ) 2 ( x – 1 ) + 2 ( x – 1 ) 2 = ( x – 1 ) 2 ( x – 1 + 2 ) = ( x – 1 ) 2 ( x + 1 )
nên A đúng
+ ) ( x – 1 ) 3 + 2 ( x – 1 ) = ( x – 1 ) . ( x – 1 ) 2 + 2 ( x – 1 ) = ( x – 1 ) [ ( x – 1 ) 2 + 2 ]
nên B đúng
+ ) ( x – 1 ) 3 + 2 ( x – 1 ) 2 = ( x – 1 ) ( x – 1 ) 2 + 2 ( x – 1 ) ( x – 1 ) = ( x – 1 ) [ ( x – 1 ) 2 + 2 ( x – 1 ) ] = ( x – 1 ) [ ( x – 1 ) 2 + 2 x – 2 ]
nên C đúng
+ ) ( x – 1 ) 3 + 2 ( x – 1 ) 2 = ( x – 1 ) 2 ( x + 1 ) ≠ ( x – 1 ) ( x + 3 )
nên D sai
Đáp án cần chọn là: D