Ta có: (x + y)2 = x2 + 2xy + y2 = 42 = 16 => (x2 + y2) + 2xy = 16
Mà: x2 + y2 = 10 => 2xy + 10 = 16 => 2xy = 6 => xy = 3
Mặt khác: x3 + y3 = (x + y)(x2 - xy + y2) => x3 + y3 = 4 . [ (x2 + y2) - xy ] => x3 + y3 = 4 . (10 - 3) => x3 + y3 = 4 . 7 => x3 + y3 = 28