a: Khi \(\widehat{ABC}=70^0\) thì \(\widehat{ACB}=70^0;\widehat{BAC}=40^0\)
Khi \(\widehat{BAC}=100^0\) thì \(\widehat{ABC}=\widehat{ACB}=40^0\)
Khi \(\widehat{BAC}=90^0\) thì \(\widehat{ABC}=\widehat{ACB}=45^0\)
b: Xét ΔABE và ΔACD có
AB=AC
\(\widehat{A}\) chung
AE=AD
Do đó: ΔABE=ΔACD
Suy ra: BE=CD