Các câu hỏi tương tự
so sánh biểu thức P với \(\frac{1}{2}\)biết
\(P=\frac{3}{1!+2!+3!}+\frac{4}{2!+3!+4!}+...+\frac{2017}{2015!+2016!+2017!}\)(với n!=1.2.3...n)
Cho tổng A=\(\frac{2018}{2017^2+1}+\frac{2018}{2017^2+2}+\frac{2018}{2017^2+3}+...+\frac{2018}{2017^2+n}+...+\frac{2018}{2017^2+2017}\)
(A có 2017 số hạng). Chứng tỏ A không là số nguyên
Cho:
\(\frac{x_1-1}{2017}=\frac{x_2-2}{2016}=\frac{x_3-3}{2015}=...=\frac{x_{2017}-2017}{1}vàx_1+x_2+...+x_{2017=2017\cdot2018.}Tìmx_1,x_2,x_{3,...,x_{2017}?}\)
so sánh 2 số A và B nếu
\(A=-\frac{1}{2018}-\frac{3}{2017^2}-\frac{5}{2017^3}-\frac{7}{2017^4};B=\frac{-1}{2018}-\frac{7}{2017^2}-\frac{5}{2017^3}-\frac{3}{2017^4}\)
So sánh :
\(A=\frac{2^{2018}-3}{2^{2017}-1};B=\frac{2^{2017}-3}{2^{2016}-1}\)
A frac{frac{3}{4}-frac{3}{11}+frac{3}{13}}{frac{5}{4}-frac{5}{11}+frac{5}{13}}+frac{frac{1}{2}-frac{1}{3}+frac{1}{4}}{frac{5}{4}-frac{5}{6}+frac{5}{8}}B frac{2^{12}.3^5-4^6.9^2}{left(2^2.3right)^6+8^4.3^5}-frac{5^{10}.7^3-25^5.49}{left(125.7right)^3+5^9.14^3}C frac{left(a^{2016}+b^{2016}right)^{2017}}{left(c^{2016}+d^{2016}right)^{2017}} frac{left(a^{2017}-b^{2017}right)^{2016}}{left(c^{2017}-d^{2017}right)^{2016}}
Đọc tiếp
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
C = \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}\)= \(\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-d^{2017}\right)^{2016}}\)
Sleft(-3right)^0+left(-3right)^1+left(-3right)^2+...+left(-3right)^{2017}P1-frac{1}{2}+frac{1}{3}-frac{1}{4}+...+frac{1}{2016}-frac{1}{2017}Qfrac{1}{1009}+frac{1}{1010}+frac{1}{1011}+...+frac{1}{2016}+frac{1}{2017}Ttext{ÍNH}Ttext{ỔNG}left(S,P,Qright)
Đọc tiếp
\(S=\left(-3\right)^0+\left(-3\right)^1+\left(-3\right)^2+...+\left(-3\right)^{2017}\)
\(P=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2016}-\frac{1}{2017}\)
\(Q=\frac{1}{1009}+\frac{1}{1010}+\frac{1}{1011}+...+\frac{1}{2016}+\frac{1}{2017}\)
\(T\text{ÍNH}\)\(T\text{ỔNG}\)\(\left(S,P,Q\right)\)
So sánh A và B nếu
\(A=\frac{-1}{2018}-\frac{3}{2017^2}-\frac{5}{2017^3}-\frac{7}{2017^4}\)
\(B=\frac{-1}{2018}-\frac{7}{2017^2}-\frac{5}{2017^3}-\frac{3}{2017^4}\)
So sánh \(A=\frac{2^{2018}-3}{2^{2017}-1}\) và \(B=\frac{2^{2017}-3}{2^{2016}-1}\)