\(S=1+2+2^2+2^3+....+2^8+2^9.\)
\(\Rightarrow2S=\text{}2+2^2+2^3+....+2^8+2^9+2^{10}\)
\(\Rightarrow2S-S=\left(2+2^2+2^3+....+2^8+2^9+2^{10}\right)-\left(1+2+2^2+2^3+....+2^8+2^9\right)\)
\(S=2^{10}-1=1024-1=1023< 5\cdot2^8=5\cdot256=1280\)
+) Bước 1: Rút gọn S. Ta có: S=\(2^{10}-1\)
+) Bước 2: So sánh.
Ta có: \(2^{10}-1\)\(< 2^{10}=4\cdot2^8< 5\cdot2^8=>2^{10}-1< 2^8\cdot5\left(đpcm\right)\)
HẾT!