\(\left(R1ntR2\right)\backslash\backslash R3\)
\(U=U_{12}=U_3=I_3\cdot R_3=1.15=15V\left(R_{12}\backslash\backslash R_3\right)\)
\(R=\dfrac{\left(R1+R2\right)\cdot R3}{R1+R2+R3}=\dfrac{\left(5+10\right)\cdot15}{5+10+15}=7,5\Omega\)
\(\Rightarrow I=\dfrac{U}{R}=\dfrac{15}{7,5}=2A\)