\(P=\frac{x}{y+z}+\frac{y}{z+x}+\frac{z}{x+y}=1\)
\(\Leftrightarrow\left(x+y+z\right)\left(\frac{x}{y+z}+\frac{y}{z+x}+\frac{z}{x+y}\right)=x+y+z\)
\(\Leftrightarrow\frac{x^2}{y+z}+\frac{y^2}{z+x}+\frac{z^2}{x+y}+x+y+z=x+y+z\)
\(\Rightarrow Q=\frac{x^2}{y+z}+\frac{y^2}{x+y}+\frac{z^2}{x+y}=0\) (dpcm)