theo đề bài ta có : \(x_1+x_2=\frac{1}{x_1}+\frac{1}{x_2}\Leftrightarrow x_1+x_2=\frac{x_1+x_2}{x_1x_2}\Leftrightarrow x_1x_2=1\)
\(x_1x_2=\frac{c}{a}=\frac{a^2-4a+1}{3}\)
Vậy ta có: \(a^2-4a+1=3\Leftrightarrow a^2-4a-2=0\Leftrightarrow\left[\begin{array}{nghiempt}a=2+\sqrt{6}\\a=2-\sqrt{6}\end{array}\right.\)