\(\overline{M}=16,75.2=33,5\). Áp dụng quy tắc đường chéo:
| \(NO\) (x, \(M=30\)) | \(44-33,5=10,5\) | |
| \(\overline{M}=33,5\) | ||
| \(N_2O\left(y,M=44\right)\) | \(33,5-30=3,5\) |
\(\Rightarrow\dfrac{x}{y}=\dfrac{10,5}{3,5}\Rightarrow\dfrac{x}{y}=3\Rightarrow x=3y\)
\(\%m_{NO}=\dfrac{30x}{30x+44y}.100\%=\dfrac{30.3y}{30.3y+44y}.100\%\simeq67,2\%\)
\(\Rightarrow\%m_{N_2O}=100\%-67,2\%=32,8\%\)
Đúng 0
Bình luận (0)
