Vì AB//CD
nên ΔGAB~ΔGDC
=>\(\dfrac{S_{GAB}}{S_{GDC}}=\left(\dfrac{AB}{CD}\right)^2=\dfrac{1}{9}\)
=>\(\dfrac{S_{GAB}}{S_{ABCD}}=\dfrac{1}{8}\)
=>\(S_{ABCD}=8\cdot6=48\left(cm^2\right)\)
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