Question

Cho hai đường thẳng xy và zt cắt nhau tại O tạo thành bốn góc O1ˆO1^ , O2ˆO2^ , O3ˆO3^ , O4ˆO4^ . Tính số đo bốn góc biết O1ˆ+O2ˆ+O3ˆ=240∘

Answer 1

10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

Answer 2

dm thằng súc vật nguyễn đức anh

╚{AV♀N░≡┤E╞

Answer 3

(Mình vẽ hơi xấu, mong bạn thông cảm)

Ta có \(\widehat{O}_1+\widehat{O_2}=180^o\)(kề bù)

và \(\widehat{O_1}+\widehat{O_2}+\widehat{O_3}=240^o\)(gt)

=> \(180^o+\widehat{O_3}=240^o\)

=> \(\widehat{O_3}=60^o\)

=> \(\widehat{O_3}=\widehat{O_1}=60^o\)(đối đỉnh)

Ta lại có \(\widehat{O}_2=180^o-\widehat{O_3}\)(kề bù)

và \(\widehat{O_2}=\widehat{O_4}\)(đối đỉnh)

=> \(\widehat{O_2}=\widehat{O_4}=180^o-\widehat{O_3}\)

=> \(\widehat{O_2}=\widehat{O_4}=180^o-60^o=120^o\)