\(n_{CH_3COOH}=0,1.0,1=0,01\left(mol\right)\)
PT: \(Na_2CO_3+2CH_3COOH\rightarrow2CH_3COONa+CO_2+H_2O\)
Theo PT: \(n_{CO_2}=\dfrac{1}{2}n_{CH_3COOH}=0,005\left(mol\right)\)
\(\Rightarrow V_{CO_2}=0,005.22,4=0,112\left(l\right)\)
Đáp án: A
\(n_{CH_3COOH}=0,1.0,1=0,01\left(mol\right)\\ Na_2CO_3+2CH_3COOH\rightarrow2CH_3COONa+CO_2+H_2O\\ n_{CO_2}=\dfrac{0,01}{2}=0,005\left(mol\right)\\ V_{CO_2\left(đktc\right)}=0,005.22,4=0,112\left(l\right)\\ Chọn.A\)