Từ đẳng thức \(\frac{a}{b+c}=\frac{b}{c+a}=\frac{c}{a+b}\)
\(\Rightarrow\frac{a}{b+c}+1=\frac{b}{c+a}+1=\frac{c}{a+b}+1\)
\(\Rightarrow\frac{a+b+c}{b+c}=\frac{a+b+c}{c+a}=\frac{a+b+c}{a+b}\)
Nếu a + b + c = 0
=> a + b = - c;
b + c = - a;
c + a = - b
Khi đó M = \(\frac{-c}{2c}+\frac{-a}{a}+-\frac{b}{4b}=-\frac{1}{2}+\left(-1\right)+\left(-\frac{1}{4}\right)=-\frac{7}{4}=-1,75\)
Nếu a + b + c \(\ne\)0
=> b + c = c + a = a + b
=> a = b = c
Khi đó M = \(\frac{2c}{2c}+\frac{2a}{a}+\frac{2b}{4b}=1+2+\frac{1}{2}=\frac{7}{2}=3,5\)
Vậy nếu a + b + c = 0 thì M = -1,75
nếu a + b + c \(\ne\)0 thì M = 3,5
