\(a^2+b^2+1=ab+a+b\)
\(\Rightarrow2a^2+2b^2+2=2ab+2a+2b\)
\(\Rightarrow2a^2+2b^2+2-2ab-2a-2b=0\)
\(\Rightarrow\left(a-b\right)^2+\left(a-1\right)^2+\left(b-1\right)^2=0\)
\(\Rightarrow a=b=1\)
\(S=\left(1+\dfrac{a}{b}\right)\left(1+b\right)\left(1+\dfrac{1}{a}\right)=\left(1+\dfrac{1}{1}\right)\left(1+1\right)\left(1+\dfrac{1}{1}\right)=8\)