Question

Cho b²=ac. CMR: \(\dfrac{a}{c}=\dfrac{a^2+b^2}{b^2+c^2}\)

Answer 1

Ai giúp đi, mik lazy lắm

Answer 2

\(\dfrac{a}{c}=\dfrac{a^2+b^2}{b^2+c^2}\)

\(VP=\dfrac{a^2+ac}{ac+c^2}=\dfrac{a\left(a+c\right)}{c\left(a+c\right)}=\dfrac{a}{c}=VT\left(đpcm\right)\)

Answer 3

\(\dfrac{a^2+b^2}{b^2+c^2}=\dfrac{a^2+ac}{ac+c^2}=\dfrac{a\left(a+c\right)}{c\left(a+c\right)}=\dfrac{a}{c}\)

Answer 4

Ta có: \(\dfrac{a^2+a.c}{a.c+c^2}=\dfrac{a\left(a+c\right)}{c\left(a+c\right)}=\dfrac{a}{c}\left(đpcm\right)\)