\(\frac{a}{k}=\frac{x}{a}\Rightarrow a^2=k.x\)
\(\frac{b}{k}=\frac{y}{b}\Rightarrow b^2=k.y\)
\(=\frac{a^2}{b^2}=\frac{k.x}{k.y}=\frac{x}{y}\text{ Vậy }\frac{a^2}{b^2}=\frac{x}{y}\)
\(\frac{a}{k}=\frac{x}{a}\Rightarrow a^2=k.x\)
\(\frac{b}{k}=\frac{y}{b}\Rightarrow b^2=k.y\)
Thay vào vế trái ta có :
\(\frac{a^2}{b^2}=\frac{kx}{ky}=\frac{x}{y}\)
Vậy VT = VP
Cũng hay nhỉ