Đặt: \(\frac{a}{2013}=\frac{b}{2012}=\frac{c}{2011}=k\Rightarrow\hept{\begin{cases}a=2013k\\b=2012k\\c=2011k\end{cases}}\)
\(P=\frac{\left(a-c\right)^4}{\left(a-b\right)^2\left(b-c\right)^2}=\frac{\left(2013k-2011k\right)^4}{\left(2013k-2012k\right)^2\left(2012k-2011k\right)^2}=\frac{16k^4}{k^4}=16\)